(x+3)-[(x+2)(x^3-1)]=0

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Solution for (x+3)-[(x+2)(x^3-1)]=0 equation:


Simplifying
(x + 3) + -1[(x + 2)(x3 + -1)] = 0

Reorder the terms:
(3 + x) + -1[(x + 2)(x3 + -1)] = 0

Remove parenthesis around (3 + x)
3 + x + -1[(x + 2)(x3 + -1)] = 0

Reorder the terms:
3 + x + -1[(2 + x)(x3 + -1)] = 0

Reorder the terms:
3 + x + -1[(2 + x)(-1 + x3)] = 0

Multiply (2 + x) * (-1 + x3)
3 + x + -1[(2(-1 + x3) + x(-1 + x3))] = 0
3 + x + -1[((-1 * 2 + x3 * 2) + x(-1 + x3))] = 0
3 + x + -1[((-2 + 2x3) + x(-1 + x3))] = 0
3 + x + -1[(-2 + 2x3 + (-1 * x + x3 * x))] = 0
3 + x + -1[(-2 + 2x3 + (-1x + x4))] = 0

Reorder the terms:
3 + x + -1[(-2 + -1x + 2x3 + x4)] = 0
3 + x + -1[(-2 + -1x + 2x3 + x4)] = 0
3 + x + [-2 * -1 + -1x * -1 + 2x3 * -1 + x4 * -1] = 0
3 + x + [2 + 1x + -2x3 + -1x4] = 0

Reorder the terms:
3 + 2 + x + 1x + -2x3 + -1x4 = 0

Combine like terms: 3 + 2 = 5
5 + x + 1x + -2x3 + -1x4 = 0

Combine like terms: x + 1x = 2x
5 + 2x + -2x3 + -1x4 = 0

Solving
5 + 2x + -2x3 + -1x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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